Template:Individual-TLP-paragraph-es-6.241: Difference between revisions

Latest revision as of 16:01, 15 January 2023

6.241 Así reza la prueba de la proposición 2 × 2 = 4:

$(Ω^{ν})^{μ'} x = Ω^{ν \times μ'} x Def.$

$Ω^{2 \times 2'} x = (Ω^{2})^{2'} x = (Ω^{2})^{1 + 1'} x = Ω^{2'} Ω^{2'} x = Ω^{1 + 1'} Ω^{1 + 1'} x$

$(Ω^{'} Ω)^{'} (Ω^{'} Ω)^{'} x = Ω^{'} Ω^{'} Ω^{'} Ω^{'} x = Ω^{1 + 1 + 1 + 1'} x = Ω^{4'} x$

@@ Line 2: / Line 2: @@
 {{p center|<math>( \Omega^{ \nu} )^{\mu \prime} x = \Omega^{ \nu \times \mu \prime} x \text{ Def.}</math>}}
-{{p center|<math>( \Omega^{2 \times 2 \prime} x = (\Omega^2 )^{2 \prime} x = ( \Omega^2 )^{1+1 \prime} x = \Omega^{2 \prime} \Omega^{2 \prime} x = \Omega^{1 + 1 \prime} \Omega^{1 + 1 \prime} x</math>}}
+{{p center|<math>\Omega^{2 \times 2 \prime} x = (\Omega^2 )^{2 \prime} x = ( \Omega^2 )^{1+1 \prime} x = \Omega^{2 \prime} \Omega^{2 \prime} x = \Omega^{1 + 1 \prime} \Omega^{1 + 1 \prime} x</math>}}
 {{p center|<math>(\Omega ' \Omega)^{\prime} (\Omega ' \Omega)^{\prime} x = \Omega ' \Omega ' \Omega ' \Omega ' x = \Omega^{1 + 1 + 1 + 1 \prime} x = \Omega^{4 \prime} x</math>}}
 }}